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I have a number 'x' raised to 'n', and I want to calculate the x^n without x.x.x.x....(n times). How do I do that? Is it possible to do it without the tedious self-multiplication?

(I mean to do it without computers)

I've been suggested using logarithms, but how efficient are they and do they have a limit?

Thanks

  • You have to calculate $100^{100}$ So let $100^{100} = x$ Raising log both sides $ 100log 100=log x $ so $x$ will be antilog$200$ –  Jul 04 '21 at 06:28
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    @MichaelRozenberg It seems as if the question you linked is different to this one. Maybe you're supposed to send a related one? – soupless Jul 04 '21 at 06:35
  • Do you need an exact answer (assuming $x$ is an integer and $n$ is a nonnegative integer)? Either way, is $n$ a nonnegative integer? – Mark S. Jul 04 '21 at 06:54
  • If it's the number of multiplications that bothers you, you could reduce it by making intermediate results, for instance $3^{16}$ is $81^4$ – Déjà vu Jul 07 '21 at 03:14

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