2

There are 10 students in a class:

  1. Michael
  2. Michelle
  3. Jack
  4. Daniel
  5. James
  6. Jane
  7. Tom
  8. Thompson
  9. Chris
  10. Tracy

These are the pairs that like to talk together in class:

  1. Michael - Michelle
  2. Michael - Jack
  3. Michael - Daniel
  4. Michelle - James
  5. Michelle - Jane
  6. Jane - Tom
  7. Jane - Thompson
  8. Thompson - Chris
  9. Jack - Thompson
  10. Jack - Tracy
  11. Daniel - Tom
  12. Daniel - Chris
  13. James - Tracy
  14. James - Chris
  15. Tom - Tracy

Proof that there is no method to divide 10 students into 3 groups so that each group does not have a pair that likes to talk together.

I tried to use contradiction: Suppose that there are a way to do this. 10 students would be divided into 3 groups as such

3 - 3 - 4

I also notice that each student likes to talk to three other students

But i'm stuck here and don't know what to do next

Kain
  • 155
  • Just checked that there are a total of 20 solutions. Four for each of the five groups of four people that we can group together. – AnilCh Jul 26 '21 at 09:20

1 Answers1

1

How about:

  • Michael, Chris, Jane, Tracy
  • Michelle, Jack, Daniel
  • Tom, Thompson, James
JMP
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