There are 10 students in a class:
- Michael
- Michelle
- Jack
- Daniel
- James
- Jane
- Tom
- Thompson
- Chris
- Tracy
These are the pairs that like to talk together in class:
- Michael - Michelle
- Michael - Jack
- Michael - Daniel
- Michelle - James
- Michelle - Jane
- Jane - Tom
- Jane - Thompson
- Thompson - Chris
- Jack - Thompson
- Jack - Tracy
- Daniel - Tom
- Daniel - Chris
- James - Tracy
- James - Chris
- Tom - Tracy
Proof that there is no method to divide 10 students into 3 groups so that each group does not have a pair that likes to talk together.
I tried to use contradiction: Suppose that there are a way to do this. 10 students would be divided into 3 groups as such
3 - 3 - 4
I also notice that each student likes to talk to three other students
But i'm stuck here and don't know what to do next