The speed of the car
It is correct to take "The speed of the car is $60$ km/h" and multiply through by $1$ hour to get "The ____ of the car in $1$ hour is $60$ km". However, it is not correct to call the result "speed". The thing that the car gets $60$ km of in $1$ hour is distance traveled. We can say "The distance the car travels in $1$ hour is $60$ km".
The price of the bottles
If you're buying bottles, you measure the total amount you pay in dollars; what you measure in dollars per bottle is "unit price" (not a terribly standard term). The goal of this "unit price" is to get a property of the thing you want to buy (water or milk or olive oil) that doesn't depend on how much you buy.
In the sentence "The price of $6$ bottles of olive oil is $6$ dollars" and divide through by $6$ bottle to get "The unit price of olive oil is $6$ dollars per $6$ bottles, or $1$ dollar/bottle". Think of this as an equation separated by "is"; you must do the same thing to both sides.
If you divide by $1$ bottle on both sides instead, you still have $6$ left on both sides, and so you have "$6$ times the unit price of olive oil is $6$ dollars/bottle". A true statement, but not a very useful one.
The mass of a mole of carbon
This is a super confusing one.
From one point of view, we're not doing any division. "Molar mass" and "Mass of $1$ mole" are simply synonyms. So we can say "The mass of $1$ mole of Carbon-12 is $12$ grams" or we can say "The molar mass of Carbon-12 is $12$ grams".
From another point of view, we'd like to be able to say things like
100 g of water is about 5.551 mol of water. (Source: Wikipedia)
It sure looks like we have a "mass of water" on one side, and a "number of water molecules" on the other side.
To enable doing this without making mistakes, we write molar mass in units of g/mol, so that we can use the molar mass of a substance to convert from moles to grams. If you want to turn "$1$ mole of Carbon-12" into "$12$ grams of Carbon-12", you multiply by the molar mass of Carbon-12 in grams/mole. That unit is chosen so that the units in
$$
1 \text{ mol} \cdot 12 \text{ } \frac{\text{g}}{\text{mol}} = 12 \text{ g}
$$
cancel out.
From a third point of view, a mole is simply a number of particles, so it's unitless(?) anyway.