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I was simplifying the expression:

(K.(K.(J+L))')+(K'.(K.(J+L)))

=(K.(K'+(J+L)'))+(K.K'.(J+L))

=(1+K.(J+L)')+(J+L)

=(1+K.(J'.L'))+(J+L)

=1+K.J'.L'+J+L

However, when I was evaluating this Simplified expression using the truth table, the result did not come as expected.

For J=K=L=1, the result is:

1+(1)(0)(0)+1+1=1

While the result is supposed to be 0.

Anything's wrong with my calculations?

MsBonniePython
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  • Please, format your questions properly using MathJax. Anyway, aren't you aware that $1+X=1$, for whatever $X$? (In your case $X=KJ'L'+J+L$). Perhaps there's nothing wrong with your simplification... – amrsa Sep 23 '21 at 11:35
  • Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. – Community Sep 23 '21 at 11:35
  • In the second row: $K.K´=0,$ not $1.$ – user376343 Sep 25 '21 at 19:34

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