Figure out rate of change of speed for fixed distance

Question

Say I have two points. I know the distance between those points. And let's say I have a bobbin that's starting at point A at a fixed speed of 100 jiggers/second

By point B, I want my bobbin to only be traveling 20 jiggers/second.

What equation can I use to figure out what rate of change of speed I would need to apply to my bobbin to slow it down to 20 jiggers/second?

How would I do it so that it eased into the new speed?

I apologize if this is poorly worded or an asininely easy question. I'm a game developer, and I'm not really sure how to ask this question in a Google-friendly fashion.

So you want a constant acceleration, right? The answer will be in, say, $m/s^2$? — dfeuer, Jun 23 '13 at 15:36
Yes, exactly, $jiggers/sec^2$. At least that's what I figured. — dclowd9901, Jun 23 '13 at 15:39

score 1 · Accepted Answer · answered Jun 23 '13 at 15:45

1

This is a basic kinematics problem, in which two things are known:

The distance between points: $d$

The initial and final velocities: $v_f=100$ j/s and $v_i=20$ j/s

To find the desired acceleration, use the equation:

$$v_f^2=v_i^2+2ad$$

Where $a$ is the acceleration.

answered Jun 23 '13 at 15:45

rurouniwallace

6,266

Thanks for the link and the answer! I'll read up on it some more. – dclowd9901 Jun 23 '13 at 15:49
So, solving for $a$, it's looking like $\frac{v_{f}^2 - v_{i}^2}{2d} = a$, is that about right? – dclowd9901 Jun 23 '13 at 15:58
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@dclowd9901 Yes, that is exactly right. – rurouniwallace Jun 23 '13 at 16:12

Figure out rate of change of speed for fixed distance

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