If $V$ is finite dimensional Hilbert space, is $L^2(0,T;V)$ also finite dimensional?

Asked Jun 24 '13 at 18:10

Active Jun 24 '13 at 18:10

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I think so, but $L^2$ is infinite dimensional so I am not sure.

asked Jun 24 '13 at 18:10

workl

4

Try $V = \mathbb R$ and $T = 2\pi$. – Umberto P. Jun 24 '13 at 18:22
@UmbertoP. Your comment could be an answer. – Davide Giraudo Jun 24 '13 at 20:01

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