Here's the question:
A population of weasels grows with rate $3\%$. We define $w(k)$ to be the number of weasels after $k$ years from now, and the current number of weasels is $350$.
a) Find the difference equation that describes the population growth in year $k$ for $k=1,2,...$
b) Solve the difference equation you found in (a) (find an analytical formula for $w(k))$.
c) In how many years would we have $700$ weasels?
My solution:
a) $w(k)=1.03w(k-1)$. (Side question, does it matter if i do $w(k+1)=1.03w(k)$?).
And here the fun starts:
b) I've first did $w(0)=350$, and calculated it as $350*1.03^k$, but the provided answer was $w(k)=339.8*1.03^k$.
And that comes only from the calculation $w(1)=w(0)^1.03\Longrightarrow w(0)=339.8$.
So from this question and the provided answer, I got that $w(0)$
And here I got really confused:
c) $339.8*1.03^k=700\Longrightarrow k=24.44$ which means we need $25$ years atleast to get $700$ weasels.
And the provided answer for (c) was $24$, and that got me really confused, it can be done by using $350*1.03^k=700$.
Was I supposed to understand that I need to calculate $w(0)$?
Why if I use $w(0)$ in (c), I would get a wrong answer?
The point of me asking this question is to see if this question is defined correctly, or I'm making mistakes and confusing myself.
Thanks in advance.