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A coffee distributor has two types of coffee. The premium blend sells

for $\$10.50$ per kg and the standard blend sells for $\$8.25$ per kg.

The distributor wishes to create 20 kg of a mixture containing these two blends to sell at $9 per kg.

Determine how many kg of each blend should be in the mixture?

Attempt: Let the mass of the premium coffee be x kg and the standard coffee be y kg.

x+y = 20 (equation 1)

10.5x + 8.25y = 180 (equation 2)

Is the second set of equation set up correctly?

Joe
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1 Answers1

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Yes. It is correct. $\frac{(10.5x+8.25y)}{20}=9$ so $10.5x+8.25y=9*20=180$

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