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How is it possible to go from 1 to 2? I can't include images in questions, so I've linked to them.

$$R\cdot l\cdot\sum_{t=t_0}^{t_1}\frac{1}{L(t)}$$ $$R\cdot l\cdot\left(\sum_{t=0}^{t_1}\frac{1}{L(t)}-\sum_{t=0}^{t_0}\frac{1}{L(t)}\right)$$

From my understanding, the top limit is inclusive, so wouldn't the two terms when $t = 0$ cancel out in the second equation, thus changing the initial form?

plop
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curiousdweller
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  • Hi there, please attach images as images, rather than hyperlinks. And it is better if you use MathJax formatting – Prometheus Dec 06 '21 at 01:09
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    Yes, the summand for $t=0$ is supposed to cancel. There is, however, a different problem. The $t=t_0$ term does cancel and it is supposed to exist in the first formula. It should be $R\cdot l\cdot\left(\sum_{t=0}^{t_1}\frac{1}{L(t)}-\sum_{t=0}^{t_0-1}\frac{1}{L(t)}\right)$. – plop Dec 06 '21 at 01:10

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