$A$ and $B$ start running simultaneously on a circular track from point $O$ in the same direction. If the ratio of their speeds is $6 :1$ respectively, then how many times is $A$ ahead of $B$ by a quarter of the length of the track before they meet at $O$ for the first time?
Now I have found that $A$ and $B$ will meet at the starting point $O$ after $LCM(\frac{L}{6x},\frac{L}{x})=\frac{L}{x}$ hours where $L$ is the length of the track.
Now for the first time $A$ will be ahead of $B$ by a quarter of the length of the track will be $\frac{L}{20x}$ hour but how will I find the remaining number of times $A$ will be ahead of $B$ in total of $\frac{L}{x}$ hours. Please help !!!
Thanks in advance !!!