how to proof $(e^x - 1) \log(1 + x) \gt x^2$ when $x\gt 1$

Asked Dec 13 '21 at 08:17

Active Dec 13 '21 at 08:23

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I have tried to caculate the function's limit for 4th,but it is always $0$ at $0$,so I don't know how to cope with it.do I need to limit it for another time or there is some other ways easier. Thanks.

edited Dec 13 '21 at 08:23

p_square

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asked Dec 13 '21 at 08:17

sansa

What does mean "the function's limit for 4th" ? – Claude Leibovici Dec 13 '21 at 08:24
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See https://math.stackexchange.com/q/1756618/42969 or https://math.stackexchange.com/q/2750387/42969 or https://math.stackexchange.com/q/620316/42969 – all found with Approach0 – Martin R Dec 13 '21 at 08:26
I make a new function f(x)=(e^x-1)log(1+x)-x^2and give the derivative evolution sorry I wrote it limit – sansa Dec 13 '21 at 08:38

how to proof $(e^x - 1) \log(1 + x) \gt x^2$ when $x\gt 1$

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