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I recorded my own voice in an old tape recorder. When I put the device in fast forward mode my voice turned a little squeaky. I wonder if the fundamental frequency of the voice had changed? Is that possible?

JMFS
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Yes, it is possible. If it is playing faster, that is outputting the analog value that used to be at time $t$ at time $t/a$ with $a \gt 1$, for some constant value $a$, all the frequencies have been multiplied by $a$.

Ross Millikan
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  • Thanks! I forgot the time and frequency scaling property of the Fourier Transform: F{s(t/a)}(f) = a * S(a*f), for a>1 – JMFS Jul 09 '13 at 18:46