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My calculus class just started going over "Separation of Variables" where you have something like $\frac{dy}{dx} = x$ and have to solve for $y$.

I understand that to do this, one must get dx on one side and dy on the other, and then take the integral of both sides. Tonight I was assigned some homework problems, one of which looked like this:

$\frac{dr}{ds} = e^{r-2s}$ I turned this into: $r = \int e^{r-2s} ds$

However once I get to this step I am unsure of how to go further. I was thinking I would turn it into this:

$-\frac{1}{2} \int 2e^{r-2s} ds$

But I don't know how to find the integral of the e considering the fact that there are two variables in the exponent. Can anyone give me any info/tips on this topic?

Jack
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