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Let the topological space $X_n$ be obtained from $S^n$ by identifying three distinct points, i.e. $X_n = S^n/\{p, q, r\}.$ Find the fundamental group of $X_n$.

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Your space is homotopically equivalent to $S^n \bigvee_2 S^1$ (i've used a little bit exotic notation, it's the wedge sum of $S^n$ with two copies of $S^1$), can you see how?

  • Not really, could you help me a little? – dunkindonuts Jul 02 '13 at 17:35
  • I suppose that you know that if you have a cw-complex $X$ and a subcomplex $A$ which is contractible then the map $X \to X/A$ is an homotopy equivalence (chapter 0 of Hatcher). You can think of your space as a copy of $S^n$ whith three segment whith one extremity respectively in a point of {p,q,r} and the other in common, after having collapsed them to a point (example 0.8 is almost this case) – Edoardo Lanari Jul 02 '13 at 23:18