Let $M$ be a von Neumann algebra and $e$ a projector. Do you know if $Spec_{eMe}(exe)\subset Spec_M(x)$ for $x\in M$? Thank you
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No. Given any positive contraction $c$, the $2\times 2$ matrix $$ \begin{bmatrix} c& (c-c^2)^{1/2}\\ (c-c^2)^{1/2}&1-c\end{bmatrix} $$ is a projection. This allows you to construct $x$ and $e$ such that $\sigma_M(x)=\{0,1\}$ but $\sigma_{eMe}(exe)$ can be any closed subset of the unit interval.
Similarly, if $v$ is a contraction, $$ \begin{bmatrix} v& (1-vv^*)^{1/2}\\ (1-v^*v)^{1/2}&v^*\end{bmatrix} $$ is a unitary. So in this case $\sigma_M(x)$ is in the unit circle, while $\sigma_{eMe}(exe)$ can be any closed subset of the closed unit disk.
Martin Argerami
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$exe$ is positive in $eMe$ isn’t it? – Iyari Rojas Jan 02 '22 at 13:59
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Yes. Interval, not ball. Edited. – Martin Argerami Jan 02 '22 at 16:15