We are given a triangle $ABC$ and points $D$ and $E$ on $AB$, such that $AE = ED = DB$.
$F$ and $G$ are arbitrary points on $AC$ and $BC$ respectively. We want to find the product of ratios $\frac {EH}{HF} \cdot \frac{FM}{MB}$.
I have tried drawing several parallels and applying Thales theorem and then multiply but I am not getting anywhere.
I also tried to use the fact that $FE$ is the median in triangle $AFD$ and $FD$ is the median in triangle $EFb$ but still nothing.
I also attempted to extend $CB$ to take a segment $BI = BC$, so that in triangle $AIC$, $AB$ will be the median and if we extend $IB$, it will bisect the side $AC$. But I still don't see anything.
Geogebra gives the result $\frac {1}{3}$.
Any ideas please? (this is not homework or anything. I found it in a Euclidean Geometry group).

So, $ \displaystyle \frac{BA}{AE} \cdot \frac{EH}{HF} \cdot \frac{FM}{MB} = 1$
– Math Lover Jan 14 '22 at 11:47