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If $U$ is an open subset of the manifold $X$, check that $$T_x(U) = T_x(X) \text{ for } x \in U.$$

I only proved when $U$ is an open subset of the manifold $X$, which is not true for submanifolds of $X$ in general right? My thought is considering the tangent space for $\mathbb{R}^3$ is $\mathbb{R}^3$, but the tangent space for its submanifold $\mathbb{R}^2$ is $\mathbb{R}^2$.

More generally, an open subset of the manifold $X$ is a submanifold, but not all submanifolds are an open subset of the manifold $X$ - some are reduced dimensions, and some more out there that I don't know. - correct?

1LiterTears
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    You have the right idea - only submanifolds of full dimension are open. If you're not allowing manifolds with boundary then all submanifolds of full dimension are open. – Anthony Carapetis Jul 04 '13 at 04:18

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