$f: X \to Y$ is a submersion, $X$ is compact and $Y$ is connected - why $f(X)$ is open?
Assume I have proved that for an open set $U \subset X$, $f(U)$ is open.
Thank you.
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2$X \subset X$ is open. – fuglede Jul 04 '13 at 20:11
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Thank you @fuglede. I'd like to accept is as an answer if you care to put it there. – WishingFish Jul 04 '13 at 20:49
