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Take 2 triangles, $ABC$ and $OBC$, with the same base $BC$.

If $\angle A<\angle O$, then $AB+AC>OB+OC$.

This question is derived from the textbook question - for a point $O$ in the triangle $ABC$, $AB + AC > OB + OC$.

The textbook question has been solved, and the one I asked is just a more general case. Intuitively it holds, but can anyone prove it arithmetically?

user829347
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  • It doesn't look true. When angle(A) is given, $A$ belongs to a arc of circle which chord is segment $BC$ https://en.wikipedia.org/wiki/Inscribed_angle#Theorem Thus for a given angle the sum $AB + AC$ belongs to a certain interval of values. By modifying slightly the angle, the interval is slightly modified and one can find inequalities in both senses for $OB + OC$ and $AB + AC$ – Gribouillis Jan 24 '22 at 14:52

1 Answers1

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It's not true as the picture show

Essaidi
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