$$\text{Set}\; = \{0,1,2,3,4,5,6\}$$
Find the probability that a three digit number which does not have the digit $0$ chosen at the far left and is chosen at random from the set, is NOT a multiple of 5.
$$P(\text{NOT A multiple of 5}) = \dfrac{6\cdot 7 \cdot 5}{6\cdot 7\cdot 7} = \dfrac{210}{294} = \frac{5}{7}$$
Is this correct?