In the solution to an exercise I came across the following: $y^TA_N \geq c_N^T \rightarrow A_N^Ty \geq c_N$. Now I was wondering, is it in general true that an inequality remains valid when 'taking transposes on both sides'? If so, what is the proof for this?
Asked
Active
Viewed 2,338 times
1 Answers
4
Generally one says $A\ge B$, for matrices, if each entry of $A$ is $\ge$ each entry of $B$. This is true if and only if each entry of $A^T$ is $\ge$ each entry of $B^T$, i.e. $A^T\ge B^T$.
vadim123
- 82,796
-
Ah, how obvious. I should've seen that :P. Thank you! – dreamer Jul 06 '13 at 15:02