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Find the integral $$\int_{0}^{\infty}\frac{ e^{-ax^{2}}-e^{-bx^{2}} }{x}dx,$$ $a>0,\ b>0$.

I tried to split the integral and use Feynman substitution, but I got an answer that doesn't look like the right one.

I considered this integral $$\int_{0}^{∞}dy\int_{0}^{∞}e^{-ax^{2}-xy}dx.$$

Gary
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2 Answers2

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This is a Frullani integral with the choice $f(x) = e^{-x^2}$, but you have to be careful about choosing $a$ and $b$, because the "$a$" and "$b$" in your question are not the same as those in the Wikipedia article.

heropup
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  • $\int_{0}^{\infty}\frac{ e^{-ax^{n}}-e^{-bx^{n}} }{x}dx=\frac{1}{n}\int_{0}^{\infty}\frac{ e^{-at}-e^{-bt} }{t}dt$ – Svyatoslav Feb 11 '22 at 12:33
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Let $J(t)=\int_{0}^{\infty}\frac{ e^{-tx ^{2}}-e^{-x^2}}{x}dx$. Then $J’(t)= -\int_{0}^{\infty}x e^{-tx ^{2}}dx=-\frac1{2t} $ and $$\int_{0}^{\infty}\frac{ e^{-ax^{2}}-e^{-bx^{2}} }{x}dx =J(a)-J(b)=\int_b^a J’(t)dt= \frac12\ln \frac ba $$

Quanto
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