What is the relation between the Hilbert transform (in $\mathbb{R}$) and maximal functions?
Asked
Active
Viewed 219 times
1 Answers
3
For example, the real Hardy space $H^1(\mathbb R)$ can be described in two equivalent ways:
- the space of functions $f\in L^1(\mathbb R)$ such that the Hilbert transform of $f$ also belongs to $L^1$
- the space of functions $f\in L^1(\mathbb R)$ such that the maximal function $\sup_t (f*\Phi_t)$ also belongs to $L^1(\mathbb R)$. Here $\Phi_t=t^{-n}\Phi(x/t)$ and $\Phi$ can be any Schwarz function.
The Hardy-Littlewood maximal function does not have such a direct relation, since it looks only at the amplitude $|f|$, ignoring the sign.
40 votes
- 9,736
-
What is $\Phi_t$? Also, can you elaborate on your last comment? – Anonymous999 Jul 08 '13 at 21:52
-
1@Anonymous999 I added the definition of $\Phi_t$. I feel disinclined to elaborate further on the answer, seeing how little effort went into the question. – 40 votes Jul 08 '13 at 22:05
-
Ok, thank you anyways. – Anonymous999 Jul 08 '13 at 22:08