How could I plot the simple function Q=56-2P, with P on the vertical axis and Q on the horizontal axis?
One problem is that P is a locked variable so would need to use another variable and somehow rename it.
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2Try $P = (56 - Q) / 2$ – caverac Feb 19 '22 at 07:43
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2I don't know what a "locked" variable is. Let $P=0$. Then $Q=56$, right? So, the point $56$ units to the right on the horizontal axis is on the graph, right? Now, let $Q=0$. What does that make $P$? Where does that point go? What do you do with the two points you have now plotted (what kind of geometrical shape is the graph going to be?)? – Gerry Myerson Feb 19 '22 at 08:39
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Any thoughts on the matter, Orm? – Gerry Myerson Feb 20 '22 at 12:42
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Thank you @GerryMyerson and caverac . I ended up doing something along the lines of what I think you are suggesting, using caverac's suggested P = (56-Q/)2 and naming the axes accordingly. The shape, of course, is a triangle, representing a standard linear demand curve. – Orm Feb 20 '22 at 13:48
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The plot of the function is a straight line. Together with the axes, part of that straight line forms a triangle. These distinctions are important. – Gerry Myerson Feb 20 '22 at 21:40