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I'm going through a review for an upcoming exam and this has me stumped:

The line tangent to $y=f(x)$ at $x=3$ passes through the points $(0,10)$ and $(10,30)$. Find the values of $f(3)$ and $f'(3)$.

I tried basic formatting for the functions, but the preview window showed \int as not working. f' is indicating the first derivative.

Seirios
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GeoffM
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1 Answers1

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Equation of tangent is $y=2x+10$, so $f'(3)=2$. So $f(3)=16$.

To do this, note that the tangent line intersects the $y$-axis at 10. And a quick computation of the gradient gives you $\frac{30-10}{10-0}=2$. And you should be home from there.

BlackAdder
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