I am trying to understand the following problem: State the basic angle theorem needed to prove $a\cong b$ in the following figure:
The answer is: Since $\overline{AB} \perp \overline{BC}$, $B$ is a right angle and hence, $b$ is the complement of $1$. Since $a$ is complement of $1$, $a\cong b$. Ie: Complements of the same angle are congruent.
I don't understand how $b$ being complement to $1$ forces it to be congruent to $a$.
