Can we say that $log \;k2^{k-1}$ is the same as $k *log \;2^{k-1}$ ? where $k$ is a constant ?
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When in doubt try plugging in some values of $k$ and check if they are equal. – projectilemotion Mar 21 '22 at 22:21
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1I think the log identities you may be confusing are $\log_c a^b=b\log_c a$ and $\log_c ab=\log_c a + \log_c b$ – Jacob Claassen Mar 21 '22 at 22:26
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No, you can't. Unless $k=1$. – lulu Mar 21 '22 at 22:55
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@lulu or $k=2$. – projectilemotion Mar 22 '22 at 06:46
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@projectilemotion True! – lulu Mar 22 '22 at 11:36