Found it while further playing with this question.
Let $P$ be a point inside an acute triangle $ABC$ (whether it works for obtuse ones - I doubt it). Let $A'B'C'$ be the pedal triangle of $P$. Now assume that (with given constants $\lambda,\mu$) $\psi=\lambda*\alpha+\mu*\pi$, and analogous with $\beta,\gamma$ and the other angles at $P$. ($\lambda+3*\mu=2$, obviously.)
Then also $\phi=\nu*\alpha+\mu*\pi$, and again cyclically. ($\nu+3*\mu=1$, obviously.)
Random (well-known) examples.
- Let $P$ be the incenter. $\lambda=1/2,\mu=1/2,\nu=-1/2$.
- Let $P$ be the orthocenter. $\lambda=-1,\mu=1,\nu=-2$.
- Let $P$ be the circumcenter. $\lambda=2,\mu=0,\nu=1$.
I probably could solve this myself in a math exam, but my head spins from all the angles and I have a hard chess match today :-) Also, I've got a hunch that this can be generalized vastly.
