2

Let $E= \{x=(\xi_{n}: \exists n_x: \xi_m = 0 \quad \forall m>n_x \}$. We define $F=\{ x =(\xi_n) \in E : \sum_{n=1}^\infty \frac{\xi_n}{n} = 0 \}$ subspace of E. Prove that this subspace is closed.

I try proving that if $x = (\xi_n)$ is the limit of a sequence $(x_n)= (\xi_1^n, \xi_2^n,...) \subset F$.

Must verified:

  1. $\sum_{n=1}^\infty \frac{\xi_n}{n} = 0$.

  2. $\exists n \in \mathbb{N} : \xi_n = 0 \quad \forall n>m$.

We have already proved 1). But, we don´t know how to prove 2). (We are using always $||.||_2$)

  • The sequence $(x_n)$ converges in $E$ to $x$, so $x\in E$ trivially, and (2) is true. – daw Mar 29 '22 at 21:06

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