I started thinking of different cases for example suppose $2x_{1}<x_{2}$, then $x_{1}<2x_{2}$. So $Q(x_{1},x_{2})=2x_{1}+x_{2}=3x_{1}$, then $Q/3=x_{1}$. But I think this path is endless. How do you deal with an equation like this?
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Notice that for $c\in\mathbb{R}$, $Q(x_1,x_2)=c$ for each of the three following cases:
- $x_1=\dfrac{c}{3},\quad x_2\ge\dfrac{2c}{3}$
- $x_1\ge\dfrac{2c}{3},\quad x_2=\dfrac{c}{3}$
- $x_1+x_2=c,\quad \dfrac{c}{3}<x_1<\dfrac{2c}{3}$
This defines the level curve $Q(x_1,x_2)=c$
Here is a desmos graph of the level curve.
John Wayland Bales
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Thank you! I thought it could be like that but I didn´t know how to put it into a equation. – thesensei Apr 14 '22 at 18:38
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@thesensei Feel free to accept the answer. – callculus42 Jul 01 '22 at 16:58