the original question, used in Sylvester's Law of Inertia. The displayed matrix products fit with the usual method of repeated "completing the square". In the $n$ by $n$ case, about half the coefficients may be taken to be $1,$ the rest negative.
$$ Q^T D Q = H $$
$$\left(
\begin{array}{rr}
1 & 0 \\
1 & 1 \\
\end{array}
\right)
\left(
\begin{array}{rr}
1 & 0 \\
0 & - 1 \\
\end{array}
\right)
\left(
\begin{array}{rr}
1 & 1 \\
0 & 1 \\
\end{array}
\right)
= \left(
\begin{array}{rr}
1 & 1 \\
1 & 0 \\
\end{array}
\right)
$$
$$ \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc $$
$$ Q^T D Q = H $$
$$\left(
\begin{array}{rrr}
1 & 0 & 0 \\
1 & 1 & 0 \\
1 & - 1 & 1 \\
\end{array}
\right)
\left(
\begin{array}{rrr}
1 & 0 & 0 \\
0 & 1 & 0 \\
0 & 0 & - 2 \\
\end{array}
\right)
\left(
\begin{array}{rrr}
1 & 1 & 1 \\
0 & 1 & - 1 \\
0 & 0 & 1 \\
\end{array}
\right)
= \left(
\begin{array}{rrr}
1 & 1 & 1 \\
1 & 2 & 0 \\
1 & 0 & 0 \\
\end{array}
\right)
$$
$$ \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc $$
$$ Q^T D Q = H $$
$$\left(
\begin{array}{rrrr}
1 & 0 & 0 & 0 \\
1 & 1 & 0 & 0 \\
1 & 2 & 1 & 0 \\
1 & - 1 & - \frac{ 1 }{ 5 } & 1 \\
\end{array}
\right)
\left(
\begin{array}{rrrr}
1 & 0 & 0 & 0 \\
0 & 1 & 0 & 0 \\
0 & 0 & - 5 & 0 \\
0 & 0 & 0 & - \frac{ 9 }{ 5 } \\
\end{array}
\right)
\left(
\begin{array}{rrrr}
1 & 1 & 1 & 1 \\
0 & 1 & 2 & - 1 \\
0 & 0 & 1 & - \frac{ 1 }{ 5 } \\
0 & 0 & 0 & 1 \\
\end{array}
\right)
= \left(
\begin{array}{rrrr}
1 & 1 & 1 & 1 \\
1 & 2 & 3 & 0 \\
1 & 3 & 0 & 0 \\
1 & 0 & 0 & 0 \\
\end{array}
\right)
$$
$$ \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc $$
$$ Q^T D Q = H $$
$$\left(
\begin{array}{rrrrr}
1 & 0 & 0 & 0 & 0 \\
1 & 1 & 0 & 0 & 0 \\
1 & 2 & 1 & 0 & 0 \\
1 & 3 & - 7 & 1 & 0 \\
1 & - 1 & 1 & - \frac{ 9 }{ 59 } & 1 \\
\end{array}
\right)
\left(
\begin{array}{rrrrr}
1 & 0 & 0 & 0 & 0 \\
0 & 1 & 0 & 0 & 0 \\
0 & 0 & 1 & 0 & 0 \\
0 & 0 & 0 & - 59 & 0 \\
0 & 0 & 0 & 0 & - \frac{ 96 }{ 59 } \\
\end{array}
\right)
\left(
\begin{array}{rrrrr}
1 & 1 & 1 & 1 & 1 \\
0 & 1 & 2 & 3 & - 1 \\
0 & 0 & 1 & - 7 & 1 \\
0 & 0 & 0 & 1 & - \frac{ 9 }{ 59 } \\
0 & 0 & 0 & 0 & 1 \\
\end{array}
\right)
= \left(
\begin{array}{rrrrr}
1 & 1 & 1 & 1 & 1 \\
1 & 2 & 3 & 4 & 0 \\
1 & 3 & 6 & 0 & 0 \\
1 & 4 & 0 & 0 & 0 \\
1 & 0 & 0 & 0 & 0 \\
\end{array}
\right)
$$
$$ \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc $$
$$ Q^T D Q = H $$
$$\left(
\begin{array}{rrrrrr}
1 & 0 & 0 & 0 & 0 & 0 \\
1 & 1 & 0 & 0 & 0 & 0 \\
1 & 2 & 1 & 0 & 0 & 0 \\
1 & 3 & 3 & 1 & 0 & 0 \\
1 & 4 & - 9 & - \frac{ 14 }{ 19 } & 1 & 0 \\
1 & - 1 & 1 & \frac{ 1 }{ 19 } & - \frac{ 107 }{ 833 } & 1 \\
\end{array}
\right)
\left(
\begin{array}{rrrrrr}
1 & 0 & 0 & 0 & 0 & 0 \\
0 & 1 & 0 & 0 & 0 & 0 \\
0 & 0 & 1 & 0 & 0 & 0 \\
0 & 0 & 0 & - 19 & 0 & 0 \\
0 & 0 & 0 & 0 & - \frac{ 1666 }{ 19 } & 0 \\
0 & 0 & 0 & 0 & 0 & - \frac{ 1250 }{ 833 } \\
\end{array}
\right)
\left(
\begin{array}{rrrrrr}
1 & 1 & 1 & 1 & 1 & 1 \\
0 & 1 & 2 & 3 & 4 & - 1 \\
0 & 0 & 1 & 3 & - 9 & 1 \\
0 & 0 & 0 & 1 & - \frac{ 14 }{ 19 } & \frac{ 1 }{ 19 } \\
0 & 0 & 0 & 0 & 1 & - \frac{ 107 }{ 833 } \\
0 & 0 & 0 & 0 & 0 & 1 \\
\end{array}
\right)
= \left(
\begin{array}{rrrrrr}
1 & 1 & 1 & 1 & 1 & 1 \\
1 & 2 & 3 & 4 & 5 & 0 \\
1 & 3 & 6 & 10 & 0 & 0 \\
1 & 4 & 10 & 0 & 0 & 0 \\
1 & 5 & 0 & 0 & 0 & 0 \\
1 & 0 & 0 & 0 & 0 & 0 \\
\end{array}
\right)
$$
$$ \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc \bigcirc $$