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I have been looking at this problem that has no positive integer solutions, and I became curious regarding the similar following problem:

I am trying to find solutions to$\frac{a}{b}+\frac{b}{c}+\frac{c}{a}=3$, where $a,b,c \in \mathbb{N}$.

It is fairly clear that $a=b=c=1$ is a solutions, and thus, $a=b=c=d\in \mathbb{N}$ is a family of solutions where each variable is the same. (Not terribly interesting). I am curious if there are other solutions and how to find them. If not, how could one prove there exist none?

Bill Dubuque
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1 Answers1

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AM-GM gives

$$\frac{\frac{x}{y} + \frac{y}{z} + \frac{z}{x}}{3}\geq\sqrt[3]{\frac{x}{y}\cdot\frac{y}{z}\cdot\frac{z}{x}} = 1$$

Where equality is achieved when $\frac{x}{y} = \frac{y}{z} = \frac{z}{x}$. This gives $x = \frac{y^2}{z}$, and substituting gives $y^3 = z^3$ i.e. $y = z$. Therefore, the only solutions are $x = y = z = k$ where $k\in\mathbb{Z}$.

Gareth Ma
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