number when divided by 17 leaves remainder 3 and when divided by 16 leaves remainder 10 and is divisible by 15
find the smallest number in the series
i tried the conventional method but it gave me wrong answer so please help
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By the Chinese Remainder Theorem, the number is $x=3930$, which is unique modulo $4080$.
Dietrich Burde
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the no is divisible by all the numbers i.e 15,16,17 but i need a number which leaves a remainder 3 and 10 when divided by 17,16 respectively – Hemanth Kumar Jul 15 '13 at 08:40
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$3930=15\cdot 262+0=16\cdot 245+10=17\cdot 231+3$, so why are you not satisfied ? – Dietrich Burde Jul 16 '13 at 12:05