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I am told that $\dfrac{4x}{x-3}$ is equal to $4+\dfrac {12}{x-3}$, but I have no idea how to arrive at that.

Can anyone, please, break it up for me?

tomi
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brilliant
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    $\frac{4(x-3)+12}{x-3}$ – Lion Heart May 03 '22 at 14:23
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    Because this question prompted the correct answer which at 1st glance is slightly surprising, it is by definition a good question. It would have been better for the question-asker to show where his/her attempt resulted in an obstacle or something perplexing though. – Andreas ZUERCHER May 03 '22 at 14:28

1 Answers1

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\begin{equation*} 4+\frac{12}{x-3}=\frac{4(x-3)}{x-3}+\frac{12}{x-3}=\frac{4x-12+12}{x-3}=\frac{4x}{x-3} \end{equation*}

温泽海
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