Suppose that there is a triangle with altitudes $h_1$, $h_2$ and $h_3$.
Let $a_1$, $a_2$, and $a_3$ be the three sides of this triangle, such that the altitude from side $a_i$ is $h_i$. The area $A$ of the triangle is, by the well known formula:
$$
A=\frac{1}{2}a_1h_1=\frac{1}{2}a_2h_2=\frac{1}{2}a_3h_3.
$$
With this, we use the condition that for a triangle to exist, the sum of the length of its shorter sides must be bigger than the length of its longer side. In terms of altitudes, if $h_1\leq h_2\leq h_3$, the condition thus becomes
$$
\frac{1}{h_1} \leq \frac{1}{h_2}+\frac{1}{h_3},
$$
which does not hold for b) only.