0

Why are the two proofs below contradicting each other?

  • $e^{iπ} = -1 $
  • $e^{π2i}= (e^{iπ})^2 = 1$
  • $(e^{π2i})^π = 1$

Part 2

  • $(e^{π2i})^π = e^{{π^2}2i}$
  • $cos(2{π^2}) = i sin(2{π^2})$ ≠ 1

0 Answers0