Let $\Gamma$ be a discrete group of isometries of the hyperbolic plane $\mathbb{H}^2$, and let $x_0\in \mathbb{H}^2$ have trivial stabiliser. Then the set $$D(\Gamma,x_0)=\textrm{Int}(\{x\in \mathbb{H}^2\mid d(x_0,x)\le d(x_0,\gamma x)\;\forall\gamma\in\Gamma\})$$ defined as the interior of a closed set is a Dirichlet fundamental domain for $\Gamma$ centred on $x_0$. See proposition 1.10 on p 149 of Geometry II edited by EB Vinberg.
I have been searching for a reference which treats the idea of a Dirichlet fundamental domain in its most general setting (or at least a reasonably general one). For example, if $(X,d)$ is a connected (and locally connected) metric space, and $\Gamma$ acts on $X$ discretely by isometries, then is this enough to guarantee that a set defined analogously to $D(\Gamma,x_0)$ above is a fundamental domain? More generally my question is:
Question What is the most general setting (ie the weakest hypotheses on a group $\Gamma$ acting on a metric space $(X,d)$), for $D(\Gamma,x_0)$ to be a fundamental domain?
This question touches on what I am asking, but falls short of being explicit of the level of generality possible.
Edit 1: the definition of a fundamental domain I'm working with is a set $\mathcal{F}\subset X$ which satisfies:
- $\mathcal{F}$ is open and connected
- translates of its closure cover $X$: ie $\bigcup_{\gamma\in\Gamma}\gamma\overline{\mathcal{F}}=X$
- distinct translates are disjoint: ie if $\gamma\in \Gamma$ does not fix $X$ pointwise, then $\mathcal{F}\cap\gamma\mathcal{F}=\emptyset$
Edit 2: thanks to @MoisheKohan who referred me (in the comments on their answer below) to this very useful MO post along similar lines to my question. I wont go to the effort of editing my original question to become a facsimile of that post, but it points out some of the subtleties not mentioned in my question, for example
- The need for $\mathcal{F}$ to be regular in some sense
- The difficulty of defining a fundamental domain outside of the context of group actions on complete manifolds because it may be possible for a finite order group element to fix a nonempty open subset (this is illustrated in the example in the answer below)