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  1. Let $A$ be a $M \times N$ matrix and $B$ a $N \times P$ matrix. Prove that $(AB)^T = B^TA^T$.

  2. Use the result in Problem 1 and the associative property of matrix multiplication to show that $(ABC)^T$ = $C^TB^TA^T$

I already have a drafted anwswer in Problem 1. I let $C = AB$ and use the definition of matrix multiplication that the $(i,j)^{th}$ entry of $C^T$ must be equal to the $(i,j)^{th}$ entry of $B^TA^T$. Then I was having a problem with Problem 2.

Could you help me out?

user84275
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2 Answers2

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HINT: Your approach to Problem 1 is sound, though writing down the details takes a little concentration. For Problem 2, let $X=AB$; then $(ABC)'=(XC)'$, and you can use Problem 1 a couple of times to finish the argument.

Brian M. Scott
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Hint: Let $X=BC$ (this is just a change in notation). We need to prove that:

(1) $(AX)'=C'B'A'$.

You've already proven:

(2) $X'=C'B'$.

Therefore, (1) is equivalent to:

(3) (I'll let you rewrite (1) using (2))

And you've already proven (3)!

Exercise 1: If you're familiar with the principle of mathematical induction, then can you prove that $(A_1\cdots A_n)'=A_n'\cdots A_1'$ for all natural numbers $n$ using the idea I presented above?

I hope this helps!

Amitesh Datta
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