Let $A$ be a $M \times N$ matrix and $B$ a $N \times P$ matrix. Prove that $(AB)^T = B^TA^T$.
Use the result in Problem 1 and the associative property of matrix multiplication to show that $(ABC)^T$ = $C^TB^TA^T$
I already have a drafted anwswer in Problem 1. I let $C = AB$ and use the definition of matrix multiplication that the $(i,j)^{th}$ entry of $C^T$ must be equal to the $(i,j)^{th}$ entry of $B^TA^T$. Then I was having a problem with Problem 2.
Could you help me out?