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Let $X$ be the set of all real-valued bounded sequences. Let the function $d: X \times X \to [0,∞)$ be $$ d(x, y) := \sup_{i \in \mathbb{N}}\lvert x_i - y_i \rvert $$ where $x = \{x_i\}_{i\in \mathbb{N}}, y = \{y_i\}_{i\in\mathbb{N}} \in X$.

Show that $F = \{x \in X \mid d(x, 0) \leq 1\}$ is a bounded closed set which is not compact. Here $0$ denotes the zero constant sequence.

ytnb
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1 Answers1

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Hint :

  1. $F=B[0,1] $ ( closed unit ball ).

Do you know in a metric space closed ball is always a closed set?

What is the definition of a bounded set? Is the diameter of $F$ finite?

  1. Do you know in a metric space a set is compact iff every sequence a has subsequential limit in that set?

If so what about the sequence $(e_n)_{n\in\Bbb{N}} $ where $e_n$ is sequence $1$ in the $n$-th place and zeros everywhere.

Can a sequence $(x_n) $ have a convergent subsequence sequence where $d(x_m, x_n) =1$ for $m\neq n$ ?

Sourav Ghosh
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