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What is the value of $\int_C \bar{z}dz$ from $z=0$ to $z=4+2\pi i$ along the curve $C$ given by $z=t^2+it$?

1 Answers1

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Hint: parametrize it.

$$\bar{z}=t^2-it,~~~dz=(2t+i)dt$$

where $t$ is from $0$ to $2$

There should be a typo in your OP, from $z=0$ to $z=4+2i$

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