I have done a fair bit of thinking on this. Lets say that $z(f(x))=f(x+1)-f(x)$. I figured out that $z\left(\frac{x^2-x}{2}\right)=x$. But one over that does not equal $\frac{1}{x}$.
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Yes. Let $L(z)$ denote the logarithm of the gamma function.
Then $L(x + 1) - L(x) = \log(x)$. So the derivative $L'(x)$ (i.e. $\Gamma'(x) / \Gamma(x)$) satisfies the desired functional equation.
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1Great answer! Just in case someone wants to know more about $L(z)$, it's also known as the Digamma function. – Robert Lee Aug 04 '22 at 23:26
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1What's the domain of this function? It's not defined where $\Gamma(x)<0$. Of course, the original question runs into trouble at $x=0$, anyway. – Gerry Myerson Aug 04 '22 at 23:26
- going to mathoverflow when your reputation or experience is very low is something i do not recommend.
- as for tetration , you asked for a plot , but there are infinitely many tetrations !! So as stated the question was not solvable.
- For tetration there is the tetration forum
– mick Feb 18 '23 at 22:48