Let $S = \left\{ {\left( {x,y} \right) \in \mathbb{N}\times \mathbb{N} :9{{\left( {x - 3} \right)}^2} + 16{{\left( {y - 4} \right)}^2} \le 144} \right\}$
$T = \left\{ {\left( {x,y} \right) \in \mathbb{R} \times \mathbb{R} :{{\left( {x - 7} \right)}^2} + {{\left( {y - 4} \right)}^2} \le 36} \right\}$
then find the value of $n\left( {S \cap T} \right)$
Set $S$ represent an ellipse $\frac{{{{\left( {x - 3} \right)}^2}}}{{16}} + \frac{{{{\left( {y - 4} \right)}^2}}}{9} \le 1$ where $(x,y)$ are Natural Numbers.
Set $T$ represent a circle ${{{\left( {x - 7} \right)}^2} + {{\left( {y - 4} \right)}^2} \le 36}$ where $(x,y)$ are Real Numbers
Not able to do this problem , how do we proceed and get the result although I have calculated 27 from the graph

