If $f_1(n) ∈ O(g_1(n))$ and $f_2(n) ∈ O(g_2(n))$ show that $f_1(n)+f_2(n) ∈ O(max(g_1(n), g_2(n)))$
I know that: $$f(n) ∈ O(g(n)) \iff \exists\ C >0, n_0\geq0\ | f(n) \leq C *g(n)\ \forall\ n\geq{n_0}$$
How to get proof with this information?
If $f_1(n) ∈ O(g_1(n))$ and $f_2(n) ∈ O(g_2(n))$ show that $f_1(n)+f_2(n) ∈ O(max(g_1(n), g_2(n)))$
I know that: $$f(n) ∈ O(g(n)) \iff \exists\ C >0, n_0\geq0\ | f(n) \leq C *g(n)\ \forall\ n\geq{n_0}$$
How to get proof with this information?