How to get the power series expansion of 1/(1-z^2-z) at z=0? I have tried many ways but failed to find the law of the coefficients.
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Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. – Community Sep 10 '22 at 19:12
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I have tried to get the derivative but after some times it’s kind of unrealistic for me to keep dong so. – May Sep 10 '22 at 19:14
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1This was asked just some minutes ago: https://math.stackexchange.com/questions/4528782/the-coefficients-of-the-power-series-frac11-z-z2-centered-at-0-are-the – DonAntonio Sep 10 '22 at 19:18
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Does this answer your question? The coefficients of the power series $\frac{1}{1-z-z^2}$ centered at $0$ are the numbers in the Fibonacci sequence – InanimateBeing Sep 10 '22 at 19:49