In the given figure, find the $MO\times MS$ of the circle:
Given that $MP = 16$ and $MQ = 10$
I know I have to prove $\triangle PSM$ and $\triangle NQM$ similar to get ratio.
In the given figure, find the $MO\times MS$ of the circle:
Given that $MP = 16$ and $MQ = 10$
I know I have to prove $\triangle PSM$ and $\triangle NQM$ similar to get ratio.
$\angle P = \angle N$, ($\angle$ 's subtended same segment)
$\angle S=\angle Q=90^ \circ$
$\angle PMS = \angle NMQ$, (3rd $\angle$ of $\triangle$)
$\triangle PMS\sim \triangle NMQ$, (AAA similarity)
$$\frac{PM}{NM}=\frac{MS}{MQ}, \frac{16}{2\times MO}=\frac{MS}{10} $$ $$MO \times MS=80$$