I solved it by just trying out various x's, but is there a better way to solve this and how is this 'brute force' way of solving called?
I am sorry, I don't know the terminology exactly.
I solved it by just trying out various x's, but is there a better way to solve this and how is this 'brute force' way of solving called?
I am sorry, I don't know the terminology exactly.
This looks like the problem of the interest in fiance calculations.
The equation write $$13500\frac{ (x+1)^{23}-1}{x(x+1)^{22}}=250000$$ Since we cannot find the roots of a polynomial of degree $23$, we need either numerical methods or approximations.
Rewriting it as $$(x+1)^{23}-1-\frac{500}{27}x(x+1)^{22}=0$$ let use the binomial theorem or Taylor series around $x=0$.
Using very few terms , we then need to solve for $x$ $$\frac{121 }{27}x-\frac{4169 }{27}x^2-\frac{22561}{9}x^3=0$$ SO, at the price of a quadratic equation $$x\sim \frac{\sqrt{414373}-379}{12306} =0.0215$$ while the exact solution is $x=0.0208$.
For sure, we could do much better using more terms and using series reversion.