I just don't get how anything can be in relation to itself in any other way than being equivalent (being "the same"). How can some x be smaller/less than x? Intuitively, this makes no sense to me because if it were smaller it would not be in relation to itself, would it?
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5$5\leq 5$ is true, but $5<5$ is not. Does that really confuse you this much? – Arthur Nov 04 '22 at 06:24
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5Think about the word "or" in the phrase "less-than-or-equal." – anon Nov 04 '22 at 06:25
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2That helped, runway44 – Christelle Augustin Nov 04 '22 at 06:33
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Let $E$ be a non-empty set. A relation on $E$ is simply a subset $\mathcal{R}$ of $E\times E$.
Let $x\in E$ and $y\in E.$ We want to relate $x$ and $y$ $\color{blue}[(x,y)\in \mathcal{R}$ in this order (hence the choice of $(\xi,\eta)$ and not $\{x,y\})\color{blue}]$ or we don't want to relate $x$ and $y$ $[(x,y)\notin \mathcal{R}]$.
For example, if $E=\{1,2,3,4,5\}$ :
- $\mathcal{R}_1 $ defined by :$(x,y)\in \mathcal{R}_1 \iff x+y=4$ is $$\mathcal{R}_1 =\{(1,3),(2,2),(3,1)\}$$
- $\mathcal{R}_2 $ defined by :$(x,y)\in \mathcal{R}_2 \iff x<y$ is $$\mathcal{R}_2 =\{(1,2),..., (4,5)\}$$
- $\mathcal{R}_3 $ defined by :$(x,y)\in \mathcal{R}_3 \iff x$ less-than-$\color{red}{or}$-equal $ y$ $$\mathcal{R}_2 =\{(1,1),..., (5,5)\}$$

Stéphane Jaouen
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