I'm a totally amateur mathematician who discovered elliptic curves this past summer and am quite fascinated by them. I am trying to learn more about them, but I am hampered by having studied Abstract Algebra 35 years and not remembering such things as what a field or Galois Theory is. I'm trying to fill in gaps by YouTube videos, but it is slow-going now. I do know what a group is and in particular what an abelian group is, but that's about all I understand in some of the highly technical materials I've come across.
I have read about something called a Torsion Point. However, almost everything I find about them throws in all of these advanced math concepts such as fields. But instead of coming right out here and asking all of you for a plain English definition of a Torsion Point, please let me ask my own question and see if I have the right idea.
The elliptic curve in question is $y^2=x^3-3x+34$. (Correction of 18 to 34 in that equation - I copied the wrong one from my source document.) The points that are both rational and integers are $(-3,4)$, $(-3,-4)$, $(-1,6)$, $(-1,-6)$, $(2,6)$, $(2,-6)$, $(5,12)$, $(5,-12)$, $(15,58)$, $(15,-58)$, $(29,156)$, and $(29,-156)$. I found that if I started with $P:(5,12)$, the next points became $2P:(-1,6)$, $3P:(-3,-4)$, $4P:(2,-6)$, $5P:(29,-156)$, $6P:(15,58)$. At this point, the multiples of $P$ cease being integers and probably continue infinitely.
Here's my question: is the starting point $P:(5,12)$ the Torsion Point of this elliptic curve? I happened upon it as the first one of the sequence of integer points by trial and error, but would there be an easier way to find it? Also, would this elliptic curve be considered to have rank $= 1$, since it appears that all of the rational points turn up with just one starting point? I have seen some examples of elliptic curves with rank given, but again, sometimes the language of Abstract Algebra and other advanced math disciplines gets in the way of understanding how this is computed.
Thanks for any plain English help that anyone can give me on this.