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Need to simplify this equation:

$$(xy^{-1})/(y^2/x^3)^{-1}$$

So far I have

$= \frac{x/y}{1/(y^2/x^3)}$

But don't know what to do next. Any help much appreciated

Ali Caglayan
  • 5,726
user88720
  • 497

2 Answers2

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We have $$(xy^{-1})/(y^2/x^3)^{-1}=(xy^{-1})\times\left(\frac{y^2}{x^3}\right)^{+1}=\frac{x}{y}\times\frac{y^2}{x^3}=\frac{y}{x^2}$$ provided $$x\ne0, y\ne0$$

Mikasa
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2

Hint: Use $x^a x^b = x^{a+b}$ and $1/x^a = x^{-a}$ to simplify equation to form something like $x^a y^b$.

JiminP
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