2

Given $m_1, m_2$ and we know that $$a \equiv c \pmod{m_1}$$ Is there a way to directly compute $$a \pmod{m_2}$$

roxrook
  • 12,081

1 Answers1

4

If $m_2$ divides $m_1$ we can. Otherwise we cannot. The reason is that unless $m_2$ divides $m_1$, there will be more than one number $x$ such that $0\le x\lt m_2$ and $x\equiv c\pmod{m_2}$.

Remark: In connection with your question, we should mention the Chinese Remainder Theorem. If $m_1$ and $m_2$ are relatively prime, then for any $d$ we like, there will be an $a$ such that $a\equiv c\pmod{m_1}$ and $x\equiv d\pmod{m_2}$. Thus in the relatively prime case, knowing $c$ gives absolutely no information about the remainder when $a$ is divided by $m_2$.

André Nicolas
  • 507,029